So, we were standing at 3b the last time.

I then found out that there was a bit of confusion

why here

you can see the cursor

why here suddenly in the further course when the

was used, there was no minus more of the diffusion constant.

I wrote it down here

once again.

We did not use it like that, minus dCi minus C0, but we have

again minus 1

so that means dC0 minus Ci

so to speak

once again the

the symbol is turned around, simply that this minus disappears before the diffusion constant.

I have now noted this again because you want to write it in your

notes again so that you don't get confused when you look at it again.

So

I have also drawn this again here

we have then used it there.

Then we continue with 3C.

I will now make a short repetition of what we did last time

because we

talked about the SteelGrowth model. We then just wrote down this approach,

then at the end we had the equation for V.

Our current state.

Yes, of course, it's in the way.

Is it like that?

I can still turn it, it's getting difficult.

All right

so I hope you can still read the information on this page.

If not, you can download it quickly otherwise.

Maybe it's a little easier, I'll make it a little bigger.

Here we stopped the last time, we have this equation, that's our current state,

we want to solve it now.

That's the arrow, I'm counting on it now, and what we can still take from the

information we have.

We want 3C

this motion equation.

I'll draw this one here

this one here

we'll calculate that one now.

And for the time of

this one

I'll take X brand zero.

So we have zero at the time

where we start

zero seconds

already a certain oxide

Gx0

for that we want to solve the equation now with the two parameters a and b.